Week 2 at a glance

We will be learning and practicing to:

TODO:

#FinAid Assignment on Canvas (complete as soon as possible)

Review quiz based on class material each day (due Friday April 12, 2024)

Homework assignment 2 (due Tuesday April 16, 2024).

Week 2 Monday: Sets, functions, and algorithms

Let’s practice with functions related to some of our applications so far.

Recall: We model the collection of user ratings of the four movies Dune, Oppenheimer, Barbie, Nimona as the set \(\{-1,0,1\}^4\) . One function that compares pairs of ratings is \[d_0: \{-1,0,1\}^4 \times \{-1,0,1\}^4 \to \mathbb{R}\] given by \[d_0 (~(~ (x_1, x_2, x_3, x_4), (y_1, y_2, y_3, y_4) ~) ~) = \sqrt{ (x_1 - y_1)^2 + (x_2 - y_2)^2 + (x_3 -y_3)^2 + (x_4 -y_4)^2}\]

Notice: any ordered pair of ratings is an okay input to \(d_0\).

Notice: there are (at most) \[(3 \cdot 3 \cdot 3 \cdot 3)\cdot (3 \cdot 3 \cdot 3 \cdot 3) = 3^8 = 6561\] many pairs of ratings. There are therefore lots and lots of real numbers that are not the output of \(d_0\).

Recall: RNA is made up of strands of four different bases that encode genomic information in specific ways.
The bases are elements of the set \(B = \{\texttt{A}, \texttt{C}, \texttt{U}, \texttt{G}\}\). The set of RNA strands \(S\) is defined (recursively) by: \[\begin{array}{ll} \textrm{Basis Step: } & \texttt{A}\in S, \texttt{C}\in S, \texttt{U}\in S, \texttt{G}\in S \\ \textrm{Recursive Step: } & \textrm{If } s \in S\textrm{ and }b \in B \textrm{, then }sb \in S \end{array}\] where \(sb\) is string concatenation.

Pro-tip: informal definitions sometime use \(\cdots\) to indicate “continue the pattern”. Often, to make this pattern precise we use recursive definitions.

Name Domain Codomain Rule Example
\(rnalen\) \(S\) \(\mathbb{Z}^+\) \[\begin{aligned} &\textrm{Basis Step:} \\ &\textrm{If } b \in B\textrm{ then } \textit{rnalen}(b) = 1 \\ &\textrm{Recursive Step:}\\ &\textrm{If } s \in S\textrm{ and } b \in B\textrm{, then }\\ &\textit{rnalen}(sb) = 1 + \textit{rnalen}(s) \end{aligned}\] \[\begin{aligned} rnalen(\texttt{A}\texttt{C}) &\overset{\text{rec step}}{=} 1 +rnalen(\texttt{A}) \\ &\overset{\text{basis step}}{=} 1 + 1 = 2 \end{aligned}\]
\(basecount\) \(S \times B\) \(\mathbb{N}\) \[\begin{aligned} &\textrm{Basis Step:} \\ &\textrm{If } b_1 \in B, b_2 \in B \textrm{ then} \\ &basecount(~(b_1, b_2)~) = \\ &\begin{cases} 1 & \textrm{when } b_1 = b_2 \\ 0 & \textrm{when } b_1 \neq b_2 \\ \end{cases}\\ &\textrm{Recursive Step:}\\ &\textrm{If } s \in S, b_1 \in B, b_2 \in B\\ &basecount(~(sb_1, b_2)~) = \\ &\begin{cases} 1 + \textit{basecount}(~(s, b_2)~) & \textrm{when } b_1 = b_2 \\ \textit{basecount}(~(s, b_2)~) & \textrm{when } b_1 \neq b_2 \\ \end{cases} \end{aligned}\] \[\begin{aligned} basecount(~(\texttt{A}\texttt{C}\texttt{U}, \texttt{C})~) = \end{aligned}\]
\(2\) to the power of” \(\mathbb{N}\) \(\mathbb{N}\) \[\begin{aligned} &\textrm{Basis Step:} \\ &2^0= 1 \\ &\textrm{Recursive Step:}\\ &\textrm{If } n \in \mathbb{N}, 2^{n+1} = \phantom{2 \cdot 2^n} \end{aligned}\]
\(b\) to the power of \(i\) \(\mathbb{Z}^+ \times \mathbb{N}\) \(\mathbb{N}\) \[\begin{aligned} &\textrm{Basis Step:} \\ &b^0 = 1 \\ &\textrm{Recursive Step:}\\ &\textrm{If } i \in \mathbb{N}, b^{i+1} = b \cdot b^i \end{aligned}\]

Integer division and remainders (aka The Division Algorithm) Let \(n\) be an integer and \(d\) a positive integer. There are unique integers \(q\) and \(r\), with \(0 \leq r < d\), such that \(n = dq + r\). In this case, \(d\) is called the divisor, \(n\) is called the dividend, \(q\) is called the quotient, and \(r\) is called the remainder.

Because these numbers are guaranteed to exist, the following functions are well-defined:

Because these functions are so important, we sometimes use the notation \(n \textbf{ div } d = \textbf{ div } ( ~(n,d)~)\) and \(n \textbf{ mod } d = \textbf{ mod } (~(n,d)~)\).

Pro-tip: The functions \(\textbf{ div }\) and \(\textbf{ mod }\) are similar to (but not exactly the same as) the operators \(/\) and \(\%\) in Java and python.

Example calculations:

\(20 \textbf{ div } 4\)

\(20 \textbf{ mod } 4\)

\(20 \textbf{ div } 3\)

\(20 \textbf{ mod } 3\)

\(-20 \textbf{ div } 3\)

\(-20 \textbf{ mod } 3\)

Week 2 Wednesday: Representing numbers

Modeling uses data-types that are encoded in a computer. The details of the encoding impact the efficiency of algorithms we use to understand the systems we are modeling and the impacts of these algorithms on the people using the systems. Case study: how to encode numbers?

Definition For \(b\) an integer greater than \(1\) and \(n\) a positive integer, the base \(b\) expansion of \(n\) is \[(a_{k-1} \cdots a_1 a_0)_b\] where \(k\) is a positive integer, \(a_0, a_1, \ldots, a_{k-1}\) are (symbols for) nonnegative integers less than \(b\), \(a_{k-1} \neq 0\), and \[n = \sum_{i=0}^{k-1} a_{i} b^{i}\]

Notice: The base \(b\) expansion of a positive integer \(n\) is a string over the alphabet \(\{x \in \mathbb{N} \mid x < b\}\) whose leftmost character is nonzero.

Base \(b\) Collection of possible coefficients in base \(b\) expansion of a positive integer
Binary (\(b=2\)) \(\{0,1\}\)
Ternary (\(b=3\)) \(\{0,1, 2\}\)
Octal (\(b=8\)) \(\{0,1, 2, 3, 4, 5, 6, 7\}\)
Decimal (\(b=10\)) \(\{0,1, 2, 3, 4, 5, 6, 7, 8, 9\}\)
Hexadecimal (\(b=16\)) \(\{0,1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F\}\)
letter coefficient symbols represent numerical values \((A)_{16} = (10)_{10}\)
\((B)_{16} = (11)_{10} ~~(C)_{16} = (12)_{10} ~~ (D)_{16} = (13)_{10} ~~ (E)_{16} = (14)_{10} ~~ (F)_{16} = (15)_{10}\)

Examples:

\((1401)_{2}\)

\((1401)_{10}\)

\((1401)_{16}\)

Algorithms can be expressed in English or in more formalized descriptions like pseudocode or fully executable programs.

Sometimes, we can define algorithms whose output matches the rule for a function we already care about. Consider the (integer) logarithm function \[logb : \{b \in \mathbb{Z} \mid b >1 \} \times \mathbb{Z}^+ ~~\to~~ \mathbb{N}\] defined by \[logb (~ (b,n)~) = \text{greatest integer } y \text{ so that } b^y \text{ is less than or equal to } n\]

procedure \(logb\)(\(b\),\(n\): positive integers with \(b > 1\)) \(i\) := \(0\) while \(n\) > \(b-1\) \(i\) := \(i + 1\) \(n\) := \(n\) div \(b\) return \(i\) \(\{ i\) holds the integer part of the base \(b\) logarithm of \(n\}\)

Trace this algorithm with inputs \(b=3\) and \(n=17\)

\(b\) \(n\) \(i\) \(n > b-1\)?
Initial value  \(3\)  \(17\)
After 1 iteration
After 2 iterations
After 3 iterations

Compare: does the output match the rule for the (integer) logarithm function?

Two algorithms for constructing base \(b\) expansion from decimal representation

Most significant first: Start with left-most coefficient of expansion (highest value)

Informally: Build up to the value we need to represent in “greedy” approach, using units determined by base.

procedure \(\textit{baseb1}\)(\(n, b\): positive integers with \(b > 1\)) \(v\) := \(n\) \(k\) := \(1 +\) output of \(logb\) algorithm with inputs \(b\) and \(n\) for \(i\) := \(1\) to \(k\) \(a_{k-i}\) := \(0\) while \(v \geq b^{k-i}\) \(a_{k-i}\) := \(a_{k-i} + 1\) \(v\) := \(v - b^{k-i}\) return \((a_{k-1}, \ldots, a_0) \{(a_{k-1} \ldots a_0)_b~\textrm{ is the base } b \textrm{ expansion of } n \}\)

Least significant first: Start with right-most coefficient of expansion (lowest value)

Idea: (when \(k > 1\)) \[\begin{aligned} n &= a_{k-1} b^{k-1} + \cdots + a_1 b + a_0 \\ &= b ( a_{k-1} b^{k-2} + \cdots + a_1) + a_0 \end{aligned}\] so \(a_0 = n \textbf{ mod } b\) and \(a_{k-1} b^{k-2} + \cdots + a_1 = n \textbf{ div } b\).

procedure \(\textit{baseb2}\)(\(n, b\): positive integers with \(b > 1\)) \(q\) := \(n\) \(k\) := \(0\) while \(q \neq 0\) \(a_{k}\) := \(q\) mod \(b\) \(q\) := \(q\) div \(b\) \(k\) := \(k+1\) return \((a_{k-1}, \ldots, a_0) \{(a_{k-1} \ldots a_0)_b~\textrm{ is the base } b \textrm{ expansion of } n \}\)

Week 2 Friday: Algorithms for numbers

Find and fix any and all mistakes with the following:

Practice: write an algorithm for converting from base \(b_1\) expansion to base \(b_2\) expansion:

Definition For \(b\) an integer greater than \(1\), \(w\) a positive integer, and \(n\) a nonnegative integer \(\underline{\phantom{\hspace{1in}}}\),   the base \(b\) fixed-width \(w\) expansion of \(n\) is \[(a_{w-1} \cdots a_1 a_0)_{b,w}\] where \(a_0, a_1, \ldots, a_{w-1}\) are nonnegative integers less than \(b\) and \[n = \sum_{i=0}^{w-1} a_{i} b^{i}\]

Decimal Binary Binary fixed-width \(10\) Binary fixed-width \(7\) Binary fixed-width \(4\)
\(b=10\) \(b=2\) \(b=2\), \(w = 10\) \(b=2\), \(w = 7\) \(b=2\), \(w = 4\)
\((20)_{10}\)

Definition For \(b\) an integer greater than \(1\), \(w\) a positive integer, \(w'\) a positive integer, and \(x\) a real number the base \(b\) fixed-width expansion of \(x\) with integer part width \(w\) and fractional part width \(w'\) is \((a_{w-1} \cdots a_1 a_0 . c_{1} \cdots c_{w'})_{b,w,w'}\) where \(a_0, a_1, \ldots, a_{w-1}, c_1, \ldots, c_{w'}\) are nonnegative integers less than \(b\) and \[x \geq \sum_{i=0}^{w-1} a_{i} b^{i} + \sum_{j=1}^{w'} c_{j} b^{-j} \hfill \textrm{\qquad and \qquad} \hfill x < \sum_{i=0}^{w-1} a_{i} b^{i} + \sum_{j=1}^{w'} c_{j} b^{-j} + b^{-w'}\]

\(3.75\) in fixed-width binary,
integer part width \(2\),
fractional part width \(8\)
\(0.1\) in fixed-width binary,
integer part width \(2\),
fractional part width \(8\)

image

Note: Java uses floating point, not fixed width representation, but similar rounding errors appear in both.

Representing negative integers in binary: Fix a positive integer width for the representation \(w\), \(w >1\).

To represent a positive integer \(n\) To represent a negative integer \(-n\)
\([ 0a_{w-2} \cdots a_0]_{s,w}\), where \(n = (a_{w-2} \cdots a_0)_{2,w-1}\) \([1a_{w-2} \cdots a_0]_{s,w}\) , where \(n = (a_{w-2} \cdots a_0)_{2,w-1}\)
Example \(n=17\), \(w=7\): Example \(-n=-17\), \(w=7\):
\([0a_{w-2} \cdots a_0]_{2c,w}\), where \(n = (a_{w-2} \cdots a_0)_{2,w-1}\) \([1a_{w-2} \cdots a_0]_{2c,w}\), where \(2^{w-1} - n = (a_{w-2} \cdots a_0)_{2,w-1}\)
Example \(n=17\), \(w=7\): Example \(-n=-17\), \(w=7\):

For positive integer \(n\), to represent \(-n\) in \(2\)s complement with width \(w\),

Challenge: use definitions to explain why each of these approaches works.

Representing \(0\):

So far, we have representations for positive and negative integers. What about \(0\)?

To represent a non-negative integer \(n\) To represent a non-positive integer \(-n\)
\([ 0a_{w-2} \cdots a_0]_{s,w}\), where \(n = (a_{w-2} \cdots a_0)_{2,w-1}\) \([1a_{w-2} \cdots a_0]_{s,w}\) , where \(n = (a_{w-2} \cdots a_0)_{2,w-1}\)
Example \(n=0\), \(w=7\): Example \(-n=0\), \(w=7\):
\([0a_{w-2} \cdots a_0]_{2c,w}\), where \(n = (a_{w-2} \cdots a_0)_{2,w-1}\) \([1a_{w-2} \cdots a_0]_{2c,w}\), where \(2^{w-1} - n = (a_{w-2} \cdots a_0)_{2,w-1}\)
Example \(n=0\), \(w=7\): Example \(-n=0\), \(w=7\):

Review Quiz

  1. Functions and algorithms

    1. What is a recursive definition of the set \(\mathbb{Z}^+ \times \mathbb{N}\) that is the domain of the function “\(b\) to the power of \(i\)”? For convenience, we’ll refer to this set as \(X\) in the options below.

      1. Basis step: \((1,0) \in X\). Recursive step: If \((m,n) \in X\) then \((m+1, n+1) \in X\) too.

      2. Basis step: \((1,0) \in X\). Recursive step: If \((m,m-1) \in X\) then \((m+1, m) \in X\) too.

      3. Basis step: \((b,0) \in X\) for each \(b \in \mathbb{Z}^+\). Recursive step: If \((m,n) \in X\) then \((m+1, n+1) \in X\) too.

      4. Basis step: \((b,0) \in X\) for each \(b \in \mathbb{Z}^+\). Recursive step: If \((m,n) \in X\) then \((m, n+1) \in X\) too.

      5. None of the above.

    2. When running the algorithm \(logb\) for calculating the integer part of base \(b\) logarithm with inputs \(b=4\) and \(n=25\), which of the following calculations are helpful? Select all and only the calculations that are both relevant to the algorithm trace and are correct.

      1. \(25 \textbf{ div } 4 = 5\)

      2. \(25 \textbf{ div } 4 = 6\)

      3. \(25 \textbf{ div } 4 = 1\)

      4. \(4 \textbf{ div } 25 = 0\)

      5. \(4 \textbf{ div } 25 = 5\)

      6. \(4 \textbf{ div } 25 = 1\)

      7. \(6 \textbf{ div } 4= 1\)

      8. \(5 \textbf{ div } 4= 1\)

      9. \(4 \textbf{ div } 4= 1\)

  2. Base expansions

    1. Give the value (using usual mathematical conventions) of each of the following base expansions.

      1. \((10)_{2}\)

      2. \((10)_{4}\)

      3. \((17)_{16}\)

      4. \((211)_{3}\)

      5. \((3)_{8}\)

    2. Recall the definitions from class for number representations for base \(b\) expansion of \(n\), base \(b\) fixed-width \(w\) expansion of \(n\), and base \(b\) fixed-width expansion of \(x\) with integer part width \(w\) and fractional part width \(w'\).

      For example, the base \(2\) (binary) expansion of \(4\) is \(\qquad (100)_2 \qquad\) and the base \(2\) (binary) fixed-width \(8\) expansion of \(4\) is \(\qquad (00000100)_{2,8} \qquad\) and the base \(2\) (binary) fixed-width expansion of \(4\) with integer part width \(3\) and fractional part width \(2\) of \(4\) is \(\qquad (100.00)_{2,3,2} \qquad\)

      Compute the listed expansions. Enter your number using the notation for base expansions with parentheses but without subscripts. For example, if your answer were \((100)_{2,3}\) you would type (100)2,3 into Gradescope.

      1. Give the binary (base \(2\)) expansion of the number whose octal (base \(8\)) expansion is \[(371)_8\]

      2. Give the decimal (base \(10\)) expansion of the number whose octal (base \(8\)) expansion is \[(371)_8\]

      3. Give the octal (base \(8\)) fixed-width \(3\) expansion of \((9)_{10}\) .

      4. Give the ternary (base \(3\)) fixed-width \(8\) expansion of \((9)_{10}\) .

      5. Give the hexadecimal (base \(16\)) fixed-width \(6\) expansion of \((16711935)_{10}\) .1

      6. Give the hexadecimal (base \(16\)) fixed-width \(4\) expansion of \[(1011~ 1010 ~ 1001~ 0000 )_2\] Note: the spaces between each group of 4 bits above are for your convenience only. How might they help your calculations?

      7. Give the binary fixed width expansion of \(0.125\) with integer part width \(2\) and fractional part width \(4\).

      8. Give the binary fixed width expansion of \(1\) with integer part width \(2\) and fractional part width \(3\).

    3. Select all and only the correct choices below.

      1. Suppose you were told that the positive integer \(n_1\) has the property that \(n_1 \textbf{ div } 2 = 0\). Which of the following can you conclude?

        1. \(n_1\) has a binary (base \(2\)) expansion

        2. \(n_1\) has a ternary (base \(3\)) expansion

        3. \(n_1\) has a hexadecimal (base \(16\)) expansion

        4. \(n_1\) has a base \(2\) fixed-width \(1\) expansion

        5. \(n_1\) has a base \(2\) fixed-width \(20\) expansion

      2. Suppose you were told that the positive integer \(n_2\) has the property that \(n_2 \textbf{ mod } 4 = 0\). Which of the following can you conclude?

        1. the leftmost symbol in the binary (base \(2\)) expansion of \(n_2\) is \(1\)

        2. the leftmost symbol in the base \(4\) expansion of \(n_2\) is \(1\)

        3. the rightmost symbol in the base \(4\) expansion of \(n_2\) is \(0\)

        4. the rightmost symbol in the octal (base \(8\)) expansion of \(n_2\) is \(0\)

    4. Recall the definitions of signed integer representations from class: sign-magnitude and 2s complement.

      1. Give the 2s complement width 6 representation of the number represented in binary fixed-width 5 representation as \((00101)_{2,5}\).

      2. Give the 2s complement width 6 representation of the number represented in binary fixed-width 5 representation as \((10101)_{2,5}\).

      3. Give the 2s complement width 4 representation of the number represented in sign-magnitude width 4 as \([1111]_{s,4}\).

      4. Give the sign magnitude width 4 representation of the number represented in 2s complement width 4 as \([1111]_{2c,4}\).

      5. Give the sign magnitude width 6 representation of the number represented in sign magnitude width 4 as \([1111]_{s,4}\).

      6. Give the 2s complement width 6 representation of the number represented in 2s complement width 4 as \([1111]_{2c,4}\).

  3. Multiple representations

    We saw last week that, mathematically, a color can be represented as a \(3\)-tuple \((r, g, b)\) where \(r\) represents the red component, \(g\) the green component, \(b\) the blue component and where each of \(r\), \(g\), \(b\) must be from the collection \(\{x \in \mathbb{N}\mid 0 \leq x \leq 255 \}\). As an alternative representation, in this assignment we’ll use base \(b\) fixed-width expansions to represent colors as individual numbers.

    Definition: A hex color is a nonnegative integer, \(n\), that has a base \(16\) fixed-width \(6\) expansion \[n = (r_1r_2g_1g_2b_1b_2)_{16,6}\] where \((r_1r_2)_{16,2}\) is the red component, \((g_1g_2)_{16,2}\) is the green component, and \((b_1b_2)_{16,2}\) is the blue.

    1. What is the hex color corresponding to full black? Namely, this means setting the value in each of the red, green, and blue components to be the minimum \(0\).

      1. \(0\)

      2. \((0,0,0)\)

      3. \(15^{5}+15^4+15^3+15^2+15^1+1\)

      4. \(15\cdot 16^{5}+15\cdot 16^4+15\cdot 16^3+15 \cdot 16^2+15 \cdot 16^1+15\)

      5. \(16^{5}+16^4+16^3+16^2+16^1+1\)

    2. What is the hex color corresponding to full white? Namely, this means setting the value in each of the red, green, and blue components to be the maximum \(255\).

      1. \(0\)

      2. \((0,0,0)\)

      3. \(15^{5}+15^4+15^3+15^2+15^1+1\)

      4. \(15\cdot 16^{5}+15\cdot 16^4+15\cdot 16^3+15 \cdot 16^2+15 \cdot 16^1+15\)

      5. \(16^{5}+16^4+16^3+16^2+16^1+1\)

    3. Select all and only correct representations of the hex color which is full green (so the red and blue components are \(0\) and green is set to \(255\)).

      1. \((00FF00)_{16,6}\)

      2. \((00FF00)_{16}\)

      3. \(255\)

      4. \(255\cdot 256\)

      5. \(255\cdot 16^2\)

      6. \(65280\)

    4. Which of the following is a definition using set builder notation for the set of hex colors. (Select all and only correct choices)

      1. \(\{ x \in \mathbb{Z} \mid 0 \leq x \leq 16777215\}\)

      2. \(\{ x \in \mathbb{Z} \mid 0 \leq x \leq 16^6 -1\}\)

      3. \(\{ x \in \mathbb{N} \mid x \leq 16777215\}\)

      4. \(\{ x \in \mathbb{N} \mid x \leq 16^6 -1\}\)


  1. This matches a frequent debugging task – sometimes a program will show a number formatted as a base \(10\) integer that is much better understood with another representation.↩︎